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67x^2-425x-308=0
a = 67; b = -425; c = -308;
Δ = b2-4ac
Δ = -4252-4·67·(-308)
Δ = 263169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{263169}=513$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-425)-513}{2*67}=\frac{-88}{134} =-44/67 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-425)+513}{2*67}=\frac{938}{134} =7 $
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